Math Topic

by **Zurix** Sun Jan 29, 2017 6:01 pm

Hello Everybody
Welcome to Math Topic
Here we will post mathematical problems and who solve willl be genius :V
Rules
1- No Spamming [ok Thunder]
2- No Problems that its answers belong to imaginary set of numbers like [divide on zero and sqaure root of negative number]
3- No Stupid answers like [2+2 = 22]
if you answered wrong then there is not any proplem and try again

our First Question [Rate : EASY]

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Find Value of X and how you get the value

by **KAKAN** Sun Jan 29, 2017 6:06 pm

3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:06 pm

12 v:

by **Zurix** Sun Jan 29, 2017 6:07 pm

KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )

first winner but you should put another problem

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:08 pm

KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )

Shit u did it first, vut just v: do 3/6 fisrt

3/6= 2 * 6 = 12 v: easy :p

by **Zurix** Sun Jan 29, 2017 6:09 pm

if you answered it right you should post another problem

by **D4rKR420R** Sun Jan 29, 2017 6:11 pm

Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people Wink

by **Zurix** Sun Jan 29, 2017 6:13 pm

DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people

3x =24-5
3x = 19
x = 19/3
x=6.3

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:13 pm

A little impossible v: around 6

2/4 = 4/x

V:

by **KAKAN** Sun Jan 29, 2017 6:14 pm

Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem

You didn't say that. Anyways:-

Code:: f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:15 pm

Zeyad berd u sayinf we shoukd put a new problem and u dont .-.

by **KAKAN** Sun Jan 29, 2017 6:15 pm

=SdS=KrlozZ... wrote:Zeyad berd u sayinf we shoukd put a new problem and u dont .-.

You didn't answer my question Sad

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:18 pm

KAKAN wrote:
=SdS=KrlozZ... wrote:Zeyad berd u sayinf we shoukd put a new problem and u dont .-.
You didn't answer my question

Wait im e.e

by **Zurix** Sun Jan 29, 2017 6:20 pm

KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Images = {-6 , -3 , -2 , -1 , 2}

My Another Question
if x+y = z-x then z =?

by **Vipe[R]** Sun Jan 29, 2017 6:22 pm

IM HERE TO SPAM!

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:31 pm

X+y+x v:

by **=SdS=KrlozZ...** Sun Jan 29, 2017 6:32 pm

X+y+x v:

by **SJIsNotHere** Sun Jan 29, 2017 7:07 pm

Zeyad_Ahmed wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Images = {-6 , -3 , -2 , -1 , 2}

My Another Question
if x+y = z-x then z =?

Z = 2x+y

by **D4rKR420R** Sun Jan 29, 2017 7:13 pm

Zeyad_Ahmed wrote:
DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people
3x =24-5
3x = 19
x = 19/3
x=6.3

Wrong. Re-do your calculations.

KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

KAKAN is perr0. (perr0= pr0 Razz

)

by **=SdS=KrlozZ...** Sun Jan 29, 2017 7:43 pm

Ah ye 2x xD

by **Zurix** Sun Jan 29, 2017 8:17 pm

DarkRaZoR^ wrote:Here's a new problem for you all.

3x+5=24
Find the value of x and how you got it.
Note: Easy for Algebra people

3x+5 = 24
3x = 25-5
3x = 19
x = 19 /3 =6.33333333

by **Chuck Norris** Sun Jan 29, 2017 8:32 pm

KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?

by **Zurix** Sun Jan 29, 2017 10:04 pm

Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?

:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

by **Chuck Norris** Sun Jan 29, 2017 10:33 pm

Zeyad_Ahmed wrote:
Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.

by **Zurix** Sun Jan 29, 2017 10:36 pm

Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.

iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

by **Chuck Norris** Sun Jan 29, 2017 10:39 pm

Zeyad_Ahmed wrote:
Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.

by **Zurix** Sun Jan 29, 2017 10:41 pm

Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.

ok :v i will concentrate next time :v
we will wait to another one solve it

by **Chuck Norris** Sun Jan 29, 2017 10:43 pm

Zeyad_Ahmed wrote:
Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
Zeyad_Ahmed wrote:
Chuck Norris wrote:
KAKAN wrote:
Zeyad_Ahmed wrote:
KAKAN wrote:3/6 = 6/x
By cross multiplication:-
3*x = 6*6
=> 3x = 36
=> x = 36/3
=> x = 12 ( the focking answer )
first winner but you should put another problem
You didn't say that. Anyways:-
Code:
f( x ) = (x^2) - 2, x belongs to A = { -2, -1, 0, 1 ,2 }. Find the image of A and write it in roster form.

DarkRazor, your question is way too easy :p

Isn't it the image of f and not A?

The image of f is the set of all f(x) where x belongs to A.

So the answer would be {2, -1, -2, -1, 2}, but i could be wrong. My math is in Swedish so I have no idea what roster form is lol.

My math question: Garry, John and Martin have 1000 dollars in total. Martin has two times more Money than John and John has 3 times more Money than Garry. How much Money does each person have?
:v first, the images of X or F(x) called the second projection or y
btw i answered kakan's question above
let me solve yours!
let garry = x and john = y and martin = z
Garry : John : Martin : Sum
x : y : z : x+y+z
? : 3x : 2y : 1000
y = 1000/2 = 500
x = 1000/3 = 333.3
z = 1000-(x+y)
z = 1000- 833.3
z = 166.7
since x + y +z = 1000
333.3 + 500 + 166.7 = 1000
Then iam right :v
is that true :v

Wrong. Martin is supposed to have the most Money lol. You need to read the question again. Your answer to KAKANs question was wrong, unless I have missed something. Because it appears as if you get the same answer as me if you don't consider that a negative number ^2 is Always a positive number. so -2^2 is actually 4 and not -4 for example.
iam so stupid about the square of negative number :V
but your question was so clear
i used the way of ratios

But look at your answer and compare it to the text. Your answer for Martin was z = 166.7 and John y = 500. In the text it says Martin has two times more Money than John. If John really have 500 that means that Martin needs to have 1000.
ok :v i will concentrate next time :v
we will wait to another one solve it

You go ahead and try if you want to. a hint express all Money in x. you only need one variable. I have to go to bed now so cya.

by **Zurix** Sun Jan 29, 2017 10:55 pm

no man i will give up Sad

by **=SdS=KrlozZ...** Sun Jan 29, 2017 10:58 pm

Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

by Guest Sun Jan 29, 2017 11:05 pm

Error 404 - Math not found.

by **Lahhami^** Sun Jan 29, 2017 11:09 pm

[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .

by **Zurix** Sun Jan 29, 2017 11:14 pm

=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck = 25 , y = 24-(z+chuck )
zeyad +chuck + azbeee = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee

by **=SdS=KrlozZ...** Sun Jan 29, 2017 11:36 pm

Zeyad_Ahmed wrote:
=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck = 25 , y = 24-(z+chuck )
zeyad +chuck + azbeee = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee

Come on xDD its a simple problem
Just guess it

by **Zurix** Sun Jan 29, 2017 11:42 pm

[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .

it looks hard but it easy it took me 5 minutes to solve lol :v
[You must be registered and logged in to see this image.]
Done
[You must be registered and logged in to see this link.]

by **Arnold^** Mon Jan 30, 2017 3:19 am

Keep calm because maths teacher is here...

by **Lahhami^** Mon Jan 30, 2017 3:46 am

Zeyad_Ahmed wrote:
[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .
it looks hard but it easy it took me 5 minutes to solve lol :v
[You must be registered and logged in to see this image.]
Done
[You must be registered and logged in to see this link.]

wrong , use trigonometry rules xD
Hint : use this [You must be registered and logged in to see this image.]

by **=SdS=KrlozZ...** Mon Jan 30, 2017 6:02 am

[EK]Arnold^ wrote:Keep calm because maths teacher is here...

Jaja puto :v

by **Lahhami^** Mon Jan 30, 2017 6:20 am

=SdS=KrlozZ... wrote:
[EK]Arnold^ wrote:Keep calm because maths teacher is here...

Jaja puto :v

puto = ridiculous , am i right ?

by **Chuck Norris** Mon Jan 30, 2017 6:23 am

=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.

=SdS=KrlozZ... wrote:
Zeyad_Ahmed wrote:
=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

zeyad + zeyad + azbeee = 40 , zeyad = 40-(zeyad+y)
azbeee + chuck + chuck = 25 , y = 24-(z+chuck )
zeyad +chuck + azbeee = [40-(zeyad+chuck )] + [24-(z+chuck )] + azbeee

Come on xDD its a simple problem
Just guess it

You can guess on Everything, but if you don't know how to actually solve something like that, guessing won't help in the long run.

by [VF]Peter Mon Jan 30, 2017 7:12 am

LOL. Many teacher in here

by **=SdS=KrlozZ...** Mon Jan 30, 2017 7:28 am

Chuck Norris wrote:
=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.

Well many forms to do it maybe, but there should be just 1 correct solution.

by **Chuck Norris** Mon Jan 30, 2017 8:25 am

=SdS=KrlozZ... wrote:
Chuck Norris wrote:
=SdS=KrlozZ... wrote:Garry = 100
Jhon= 300
Martin = 600

Now 1 mine:

Zeyad + Zeyad + Chuck= 40
Azbee + Chuck + Chuck = 25
Chuck + Zeyad + Azbeee = ?

Correct. There are several solutions to your problem and not just one.

Well many forms to do it maybe, but there should be just 1 correct solution.

3 equations and 4 unknowns, that doesn't have 1 solution. The question mark, zeyad, azbee and Chuck is unknown.

by **=SdS=KrlozZ...** Mon Jan 30, 2017 9:14 am

Zeyad = 15
Chuck = 10
Azbee = 5

Razz

then it look like that

15 + 15 + 10 = 40
5 + 10 + 10 = 25
10 + 15 + 5 = 30

Razz

by **Zurix** Mon Jan 30, 2017 10:13 am

[EK]KillerLaham wrote:
Zeyad_Ahmed wrote:
[EK]KillerLaham wrote:[You must be registered and logged in to see this image.]

Hint : i dont mean "angle" ----> angel lol
btw its not easy .
it looks hard but it easy it took me 5 minutes to solve lol :v
[You must be registered and logged in to see this image.]
Done
[You must be registered and logged in to see this link.]
wrong , use trigonometry rules xD
Hint : use this [You must be registered and logged in to see this image.]

Sorry xD
[You must be registered and logged in to see this image.]

by **Lahhami^** Mon Jan 30, 2017 10:24 am

Zeyad_Ahmed wrote:[You must be registered and logged in to see this image.][/url]
Sorry xD
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srry to tell you that but , its also wrong xD Rolling Eyes

by **=SdS=KrlozZ...** Mon Jan 30, 2017 10:33 am

Well e.e

0,1,1,2

3,?,8,?

:p

by **Aegis** Mon Jan 30, 2017 5:17 pm

0 Divided by 0 + 1 = ?

by [FS]Jude(A) Mon Jan 30, 2017 5:58 pm

Cold wrote:0 Divided by 0 + 1 = ?

The answer is 0 as 0/0+1=0/1=0

Here my question : sin theta+alpha = a and sin theta+beta=b , then prove that cos2alpha-beta-4ab cos alpha-beta= 1-2a square- 2b square

by **Zurix** Mon Jan 30, 2017 6:46 pm

=VO=judesharp(L) wrote:
Cold wrote:0 Divided by 0 + 1 = ?

The answer is 0 as 0/0+1=0/1=0

Here my question : sin theta+alpha = a and sin theta+beta=b , then prove that cos2alpha-beta-4ab cos alpha-beta= 1-2a square- 2b square

First :v
Second According to the unknown value of Sin and the cos then we dont know what it refer to :v are you sure that you have the answer for it?

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